3[s+22]=4[s+12]

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Solution for 3[s+22]=4[s+12] equation:


Simplifying
3[s + 22] = 4[s + 12]

Reorder the terms:
3[22 + s] = 4[s + 12]
[22 * 3 + s * 3] = 4[s + 12]
[66 + 3s] = 4[s + 12]

Reorder the terms:
66 + 3s = 4[12 + s]
66 + 3s = [12 * 4 + s * 4]
66 + 3s = [48 + 4s]

Solving
66 + 3s = 48 + 4s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-4s' to each side of the equation.
66 + 3s + -4s = 48 + 4s + -4s

Combine like terms: 3s + -4s = -1s
66 + -1s = 48 + 4s + -4s

Combine like terms: 4s + -4s = 0
66 + -1s = 48 + 0
66 + -1s = 48

Add '-66' to each side of the equation.
66 + -66 + -1s = 48 + -66

Combine like terms: 66 + -66 = 0
0 + -1s = 48 + -66
-1s = 48 + -66

Combine like terms: 48 + -66 = -18
-1s = -18

Divide each side by '-1'.
s = 18

Simplifying
s = 18

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